An evaporation—crystallization process of the type described in Example 4.5.2 is used to obtain.

An evaporation—crystallization process of the type described in Example 4.5.2 is used to obtain solid potassium sulfate from an aqueous solution of this salt. The fresh feed to the process contains 19.6 wt% K2SO4.

The wet filter cake consists of solid K2SO4 crystals and a 40.0 wt% K2SO4 solution in a ratio 10 kg crystals/kg solution. The filtrate, also a 40.0% solution, is recycled to join the fresh feed. Of the water fed to the evaporator, 45.0% is evaporated. The evaporator has a maximum capacity of 175 kg water evaporated/s.

(a) Assume the process is operating at maximum capacity. Draw and label a flowchart and do the degree-of-freedom analysis for the overall system, the recycle—fresh feed mixing point, the evaporator, and the crystallizer. Then write in an efficient order (minimizing simultaneous equations) the equations you would solve to determine all unknown stream variables. In each equation circle the variable for which you would solve, but don’t do the calculations.

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